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(C) While the object is in contact with the sphere,its net acceleration is given by $a_{net} = \sqrt{a_{t}^{2} + a_{c}^{2}}$,where $a_{t} = g \sin 	h

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Increases and then becomes constant

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(C) While the object is in contact with the sphere,its net acceleration is given by $a_{net} = \sqrt{a_{t}^{2} + a_{c}^{2}}$,where $a_{t} = g \sin 	heta$ is the tangential acceleration and $a_{c} = v^{2}/R$ is the centripetal acceleration. As the object slides down,its velocity $v$ increases,which causes the net acceleration to increase.After the object loses contact with the sphere,it follows a projectile motion. During projectile motion,the only acceleration acting on the object is the acceleration due to gravity,$g$,which is constant. Therefore,the magnitude of the acceleration increases while it is on the sphere and then becomes constant $(g)$ once it is in the air.

An object is at the top of a smooth sphere which is kept fixed. As the object slides down after being given a negligible side push,what is the behavior of the magnitude of the acceleration of the object during its motion until it reaches the ground?

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